Two blocks are connected by a rope, block A has a mass of 10kg and block B has a mass of 2 kg. You push block B with a force of 12N to the right as shown below: What is the acceleration of block A? (Justify your answer) What is the force exerted by the rope? What is the torque acting on block B if its pivot is taken to be its centre, the force you apply is at the top right corner and the rope is attached to the bottom left comer of block B and block B has a height of 10cm?

Given,

Mass of block A = 10kg

Mass of block B = 2kg

Force acting on block B = 12 N

Assuming no friction is present between block and ground and tension in rope be T

considering the free dody diagram of block B, vertical force get cancelled out

and horizontal forces are : 12N – T = 2 a——— Eq.1 where a is the accelaration

considering the free dody diagram of block A, vertical force get cancelled out

and horizontal forces are : T = 10 a————Eq.2

Solving both the equation results in : **a = 1 mt/sec^2 (a)**

and the tension in the rope is **T = 10 N (b)**

Considering the free body diagram of only block B has a force 12 N at top right corner and tension in the rope 10 N at the bottom left corner acting in the same direction at center as pivot

= [12+10] 0.05

** = 1.1 N-mt (c)**