Two blocks are connected by a rope, block A has a mass of 10kg and block B has a mass of 2 kg. You push block B with a force of 12N to the right as shown below: What is the acceleration of block A? (Justify your answer) What is the force exerted by the rope? What is the torque acting on block B if its pivot is taken to be its centre, the force you apply is at the top right corner and the rope is attached to the bottom left comer of block B and block B has a height of 10cm?

Question-Answer › Category: Engineering Mechanics › Two blocks are connected by a rope, block A has a mass of 10kg and block B has a mass of 2 kg. You push block B with a force of 12N to the right as shown below: What is the acceleration of block A? (Justify your answer) What is the force exerted by the rope? What is the torque acting on block B if its pivot is taken to be its centre, the force you apply is at the top right corner and the rope is attached to the bottom left comer of block B and block B has a height of 10cm?

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Prashant asked 1 year ago

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MG answered 1 year ago

Given,
Mass of block A = 10kg
Mass of block B = 2kg
Force acting on block B = 12 N
Assuming no friction is present between block and ground and tension in rope be T
considering the free dody diagram of block B, vertical force get cancelled out
and horizontal forces are : 12N – T = 2 $*$ a——— Eq.1 where a is the accelaration
considering the free dody diagram of block A, vertical force get cancelled out
and horizontal forces are : T = 10 $*$ a————Eq.2
Solving both the equation results in : a = 1 mt/sec^2 (a)
and the tension in the rope is T = 10 N (b)
Considering the free body diagram of only block B has a force 12 N at top right corner and tension in the rope 10 N at the bottom left corner acting in the same direction at center as pivot
$\tau$ = [12+10] $*$ 0.05
$\tau$ = 1.1 N-mt (c)