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The water in a 25-m-deep reservoir is kept inside by a 90-m-wide wall whose cross section is an equilateral triangle, as shown in Fig. P3–159. Determine (a) the total force (hydrostatic + atmospheric) acting on the inner surface of the wall and its line of action and (b) the magnitude of the horizontal component of this force. Take Patm = 100 kPa.

Question-AnswerCategory: Fluid MechanicsThe water in a 25-m-deep reservoir is kept inside by a 90-m-wide wall whose cross section is an equilateral triangle, as shown in Fig. P3–159. Determine (a) the total force (hydrostatic + atmospheric) acting on the inner surface of the wall and its line of action and (b) the magnitude of the horizontal component of this force. Take Patm = 100 kPa.
John asked 4 months ago

The water in a 25-m-deep reservoir is kept inside by a 90-m-wide wall whose cross section is an equilateral triangle, as shown in Fig. P3–159. Determine (a) the total force (hydrostatic + atmospheric) acting on the inner surface of the wall and its line of action and (b) the magnitude of the horizontal component of this force. Take Patm = 100 kPa.

3-159 The water in a 25-m-deep reservoir is kept inside
by a 90-m-wide wall whose cross section is an equilateral
triangle, a

1 Answers
Mazurek Gravity answered 4 months ago

 

Solo
water
h = 25m
260
60
Pahm
Too Kla
h = 25m
width of wall (W) = 9om
Palm
(Palm tlgh)
60°
B
on the
Total force acting
wallto find the controid of
for line of action, we need
the given region.
BC=
A B [I Parmt fgn) + 2 (Parm)]
[(Protimet Sgn) + PalIn D ACD
y = Ac singo
17.0839 x singo
14.795 m
29
..y
Hence
I
578396.7166 KN
waten
from the
140 795 m
action is
and its line

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