The Water In A 25-m-deep Reservoir Is Kept Inside By A 90-m-wide Wall Whose Cross Section Is An Equilateral Triangle, As Shown In Fig. P3–159. Determine (a) The Total Force (hydrostatic + Atmospheric) Acting On The Inner Surface Of The Wall And Its Line Of Action And (b) The Magnitude Of The Horizontal Component Of This Force. Take Patm = 100 KPa.

Question-Answer › Category: Fluid Mechanics › The water in a 25-m-deep reservoir is kept inside by a 90-m-wide wall whose cross section is an equilateral triangle, as shown in Fig. P3–159. Determine (a) the total force (hydrostatic + atmospheric) acting on the inner surface of the wall and its line of action and (b) the magnitude of the horizontal component of this force. Take Patm = 100 kPa.

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John asked 4 months ago

The water in a 25-m-deep reservoir is kept inside by a 90-m-wide wall whose cross section is an equilateral triangle, as shown in Fig. P3–159. Determine (a) the total force (hydrostatic + atmospheric) acting on the inner surface of the wall and its line of action and (b) the magnitude of the horizontal component of this force. Take Patm = 100 kPa.

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Mazurek Gravity answered 4 months ago

Solo
water
h = 25m
260
60
Pahm
Too Kla
h = 25m
width of wall (W) = 9om
Palm
(Palm tlgh)
60°
B
on the
Total force acting
wall to find the controid of
for line of action, we need
the given region.
BC=
A B [I Parmt fgn) + 2 (Parm)]
[(Protimet Sgn) + Pal In D ACD
y = Ac singo
17.0839 x singo
14.795 m
29
..y
Hence
I
578396.7166 KN
waten
from the
140 795 m
action is
and its line