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The center of gravity G of a 1.5-kg unbalanced tracking wheel is located at a distance r = 18 mm from its geometric center B. The radius of the wheel is R = 60 mm and its centroidal radius of gyration is 44 mm. At the instant shown, the center B of the wheel has a velocity of 0.35 m/s and an acceleration of 1.2 m/s2, both directed to the left. Knowing that the wheel rolls without sliding and neglecting the mass of the driving yoke AB, determine the horizontal force P applied to the yoke.

Question-AnswerCategory: Engineering MechanicsThe center of gravity G of a 1.5-kg unbalanced tracking wheel is located at a distance r = 18 mm from its geometric center B. The radius of the wheel is R = 60 mm and its centroidal radius of gyration is 44 mm. At the instant shown, the center B of the wheel has a velocity of 0.35 m/s and an acceleration of 1.2 m/s2, both directed to the left. Knowing that the wheel rolls without sliding and neglecting the mass of the driving yoke AB, determine the horizontal force P applied to the yoke.
Cornwell asked 1 year ago

The center of gravity G of a 1.5-kg unbalanced tracking wheel is located at a distance r = 18 mm from its geometric center B. The radius of the wheel is R = 60 mm and its centroidal radius of gyration is 44 mm. At the instant shown, the center B of the wheel has a velocity of 0.35 m/s and an acceleration of 1.2 m/s2, both directed to the left. Knowing that the wheel rolls without sliding and neglecting the mass of the driving yoke AB, determine the horizontal force P applied to the yoke.

1 Answers
Sazid Ahmad answered 1 year ago

Step: 1

Draw the kinematic diagram as shown:
Picture 2
Here, consider  and  are positive towards left.

 

Step: 2

From the kinematic diagram,

 

Step: 3

Consider the system as follows:
Picture 1

 

Step: 4

Consider the moments about C.


 …… (1)
Here,  is the mass of the wheel,  is the radius of the wheel,  is the distance from B to G,  is the centroidal radius of gyration of the wheel,  is the acceleration of center B, and  is the velocity of center B.

 

Step: 5

Substitute  for  for  for  for  for   for  , and  for  in equation (1).

Therefore, the horizontal force P applied to the yoke is.

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