The acceleration due to gravity of a particle falling toward the earth is a = —gR2/r2,where ris the distance from the centerof the earth to the particle, Ris the radius of the earth, and g is the acceleration due to gravity at the surface of the earth. if R= 3960 mi, calculate the escape velocity,that is. the minimum velocity with which a particle must be projected vertically upw ard from the surface of the earth if it is not to return to the earth, (Hint: τ =0 for r = x.)

Question-Answer › Category: Engineering Mechanics › The acceleration due to gravity of a particle falling toward the earth is a = —gR2/r2,where ris the distance from the centerof the earth to the particle, Ris the radius of the earth, and g is the acceleration due to gravity at the surface of the earth. if R= 3960 mi, calculate the escape velocity,that is. the minimum velocity with which a particle must be projected vertically upw ard from the surface of the earth if it is not to return to the earth, (Hint: τ =0 for r = x.)

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Cornwell asked 1 year ago

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Sazid Ahmad answered 1 year ago

Step: 1

Draw the schematic diagram of the particle and the earth.

Step: 2

The acceleration due to gravity of a particle falling toward the earth is,

Here, v is the escape velocity, g is the acceleration due to gravity, R is the radius of the earth, and r is the distance from the centre of the earth to the particle.
Apply Integration on both sides,
…… (1)
Substitute for v and for r.