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Member CB of the vise shown exerts on block B a force P directed along line CB. Knowing that P must have a 1200-N horizontal component, determine (a) the magnitude of the force P(b) its vertical component.

Question-AnswerCategory: Engineering MechanicsMember CB of the vise shown exerts on block B a force P directed along line CB. Knowing that P must have a 1200-N horizontal component, determine (a) the magnitude of the force P(b) its vertical component.
Tuntun asked 1 year ago

Member CB of the vise shown exerts on block B a force P directed along line CB. Knowing that P must have a 1200-N horizontal component, determine (a) the magnitude of the force P(b) its vertical component.
4740 2 29IP1

2 Answers
Sazid Ahmad answered 1 year ago

Step: 1

Draw the free body diagram showing the horizontal and the vertical components of the force P.
719 2 29P i1

Step: 2

(a) The horizontal component of force P is 1200 N. Mathematically, it can be written as follows:
719 2 29P i2
Force P makes an angle 719 2 29P i3 with the vertical. Therefore, the angle with respect to the horizontal is obtained as below.
719 2 29P i4
From the concept of resolution of forces, the x component of force P is given as follows:
719 2 29P i5
Here, the angle is taken as 719 2 29P i6with respect to the horizontal.
Substitute 719 2 29P i7 for 719 2 29P i8 in the equation.
719 2 29P i9
Therefore, the magnitude of force P is 719 2 29P i10.
Step: 3

(b) The vertical component of the force P is given as follows:
719 2 29P i11
Substitute 719 2 29P i12 for P in the equation.
719 2 29P i13
Therefore, the magnitude of the vertical component of force P is719 2 29P i14

Anunay Sharma answered 4 months ago

Now in this question 
Pvertical =Psin 35
Phorizontal= 1200N (given)
Pcos35=1200N
P= 1464.9N 

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