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Locate the center of gravity of the sheet-metal form shown. 3) Locate the center of gravity of the sheet- metal form shown. 2.4 in. 4.8 in. 6.4 in. r = 1.8 in.

Question-Answer › Category: Engineering Mechanics › Locate the center of gravity of the sheet-metal form shown. 3) Locate the center of gravity of the sheet- metal form shown. 2.4 in. 4.8 in. 6.4 in. r = 1.8 in.
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GME asked 1 year ago

Locate the center of gravity of the sheet-metal form shown.
3) Locate the center of gravity of the sheet- metal form shown. 2.4 in. 4.8 in. 6.4 in. r = 1.8 in.

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Vikash answered 1 year ago

 
 

centre of gravity for the semicirculer - I for trianguler part 2.0 4.8 let weight for meter squeme thicknes ü considered SincWeight of 0 = 1 x 3-6 x 2.4 X Y = 4.324 Weight of ④ = 4x 3-6 X Y = 14.44 Weight of ③ = 4x 18 xy = 7.24 weight of (W = 78² Y =Now cg at aloy y ams y ty (5.089x0 +7.2% 1.2 + 19.469.441.2) - + 4.32 x 4.8 +60 2.4 cool 7. 2 14.4+4.32 orgin. : 2.73 in from

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