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Determine the force in each member of the roof truss shown. State whether each member is in tension or compression.

Question-AnswerCategory: Engineering MechanicsDetermine the force in each member of the roof truss shown. State whether each member is in tension or compression.
S cornwell asked 1 year ago

Determine the force in each member of the roof truss shown. State whether each member is in tension or compression.
 

1 Answers
Sazid Ahmad answered 1 year ago

Step: 1

Draw the free body diagram of the entire truss.
E:\Anuradha Jan2015\CF TBS\Images\714363.jpg

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Step: 2

From the geometry of the figure,
From 

From similar triangles

Calculate the angle of inclination .

 

Step: 3

From similar triangles


 

Step: 4

Take moment about A as follows:

 

Step: 5

Apply the equilibrium condition as follows:


 

 

Step: 6

Free body diagram of the joint A:
 
Picture 26

 

Step: 7

Apply the equilibrium condition as follows:





Therefore, the force acting in the member AB is 

 

Step: 8

Apply the equilibrium condition as follows:




Therefore, the force acting in the member AC is .

 

Step: 9

Draw the free body diagram of the joint B:
Picture 38

 

Step: 10

Apply the equilibrium condition as follows:



 …… (1)

 

Step: 11

Apply the equilibrium condition as follows:





 

Step: 12

Substitute  for  in equation (1).





Therefore, the force acting in the member BC is .


Therefore, the force acting in the member BD is .

 

Step: 13

Free body diagram of the joint C:
Picture 59
 

 

Step: 14

Apply the equilibrium condition as follows:
 






Therefore, the force acting in the member CD is .

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Step: 15

Apply the equilibrium condition as follows:






Therefore, the force acting in the member CE is .

 

Step: 16

Draw the free body diagram of the joint D:
Picture 74

 

Step: 17

Apply the equilibrium condition as follows:





 …… (2)

 

Step: 18

Apply the equilibrium condition as follows:






 …… (3)

 

Step: 19

Solve equations (2) and (3).


Therefore, the force acting in the member DF is .
Therefore, the force acting in the member DE is .

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Step: 20

Draw the free body diagram of the joint E:
Picture 1
 

 

Step: 21

Apply the equilibrium condition as follows:
 




Therefore, the force acting in the member EF is .

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