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An oil of specific gravity 0.8 is flowing through a venturimeter with inlet diameter of 325 mm and throat diameter of 225 mm. A differential manometer connected to the inlet and throat of the venturimeter gives a difference in the reading of 22 cm of mercury. Take coefficient of discharge of the venturimeter (Cd) as 0.96. find : 1_ Inlet area of the Venturimeter 2_Throat area of the Venturimer (in m2) 3_Differential pressure head 'h', (in m of oil) 4_Discharge of oil through Venturimeter (in m3/s 5_Discharge of oil through Venturimeter (in Litre/s)

Question-AnswerCategory: Fluid MechanicsAn oil of specific gravity 0.8 is flowing through a venturimeter with inlet diameter of 325 mm and throat diameter of 225 mm. A differential manometer connected to the inlet and throat of the venturimeter gives a difference in the reading of 22 cm of mercury. Take coefficient of discharge of the venturimeter (Cd) as 0.96. find : 1_ Inlet area of the Venturimeter 2_Throat area of the Venturimer (in m2) 3_Differential pressure head 'h', (in m of oil) 4_Discharge of oil through Venturimeter (in m3/s 5_Discharge of oil through Venturimeter (in Litre/s)
Unknown asked 1 year ago

An oil of specific gravity 0.8 is flowing through a venturimeter with inlet diameter of 325 mm and throat diameter of 225 mm. A differential manometer connected to the inlet and throat of the venturimeter gives a difference in the reading of 22 cm of mercury.
Take coefficient of discharge of the venturimeter (Cd) as 0.96.
find :
1_ Inlet area of the Venturimeter
2_Throat area of the Venturimer (in m2)
3_Differential pressure head ‘h’, (in m of oil)
4_Discharge of oil through Venturimeter (in m3/s
5_Discharge of oil through Venturimeter (in Litre/s)

1 Answers
MG answered 1 year ago

 

s-specific weight S. -0.8 X1000 = 800 N/m3 Sm= 13600 N/m3 d = 325mm = 0.325 m d₂ = 225mm = 0.225m so 22cm of 0.22am C = 0.96

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