# An amount of 502 lb of polystyrene (molar mass = 30,200 g/molar mass) is dissolved in 4,060 lb of styrene (C8H8 , molar mass =104 g/molar mass). Calculate the mass percent and mole percent of polystyrene in the mixture. You have 180 g of a 12 wt% solution of glucose (C6H12O6) in water. Calculate the molar mass of glucose and water. If 2.7 lb of CO2 is held in a vessel at 67°F and 1080 mmHg, calculate the volume (cm3 ) of the vessel using the ideal gas law.

Question-AnswerCategory: Material And Energy BalanceAn amount of 502 lb of polystyrene (molar mass = 30,200 g/molar mass) is dissolved in 4,060 lb of styrene (C8H8 , molar mass =104 g/molar mass). Calculate the mass percent and mole percent of polystyrene in the mixture. You have 180 g of a 12 wt% solution of glucose (C6H12O6) in water. Calculate the molar mass of glucose and water. If 2.7 lb of CO2 is held in a vessel at 67°F and 1080 mmHg, calculate the volume (cm3 ) of the vessel using the ideal gas law.

An amount of 502 lb of polystyrene (molar mass = 30,200 g/molar mass) is dissolved in
4,060 lb of styrene (C8H8
, molar mass =104 g/molar mass). Calculate the mass percent and
mole percent of polystyrene in the mixture. You have 180 g of a 12 wt% solution of
glucose (C6H12O6) in water. Calculate the molar mass of glucose and water. If 2.7 lb of CO2
is held in a vessel at 67°F and 1080 mmHg, calculate the volume (cm3
) of the vessel using
the ideal gas law. From ideal gas equation:

V = nRT/P
Put values
Ans V= 0.47m³