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A simple U-tube manometer containing mercury is connected to a pipe in which oil of specific gravity 0.8 is flowing. Its right limb is open to the atmosphere and the left end is connected to the pipe. The center of the pipe is 9 cm below the level of mercury (specific gravity 13.6) in the right limb. If the difference of mercury level in two limbs is 15 cm. Determine the absolute pressure of the oil in the pipe is N/cm2

Question-AnswerCategory: Fluid MechanicsA simple U-tube manometer containing mercury is connected to a pipe in which oil of specific gravity 0.8 is flowing. Its right limb is open to the atmosphere and the left end is connected to the pipe. The center of the pipe is 9 cm below the level of mercury (specific gravity 13.6) in the right limb. If the difference of mercury level in two limbs is 15 cm. Determine the absolute pressure of the oil in the pipe is N/cm2
Navneet asked 1 year ago

A simple U-tube manometer containing mercury is connected to a pipe in which oil of specific gravity 0.8 is flowing. Its right limb is open to the atmosphere and the left end is connected to the pipe. The center of the pipe is 9 cm below the level of mercury (specific gravity 13.6) in the right limb. If the difference of mercury level in two limbs is 15 cm. Determine the absolute pressure of the oil in the pipe is N/cm2.

1 Answers
Sazid Ahmad answered 1 year ago

 

Specific grarity of ofl = 5o = 0.8 - Density of ofl = sor 10 0o = lo = 0-8x 1000 I = 800 kg/m2 Specific gravity of mercury =gem 15cm Let P = pressure of oil in pipe Equating the pressure above A-A P + 2 gh, = Son Zh 5 = 33, - , , , = 13600 x 9.81 x
 

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