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A reactor's wall 320mm thick, is made up of an inner layer of fire brick (k = 0.84W/m°C) covered with a layer of insulation (k = 0.16W/m°C). The reactor operates at a temperature of 1325°C at the atmospheric temperature of 25°C. i. Calculate the thickness of brick and insulation. ii. Heat loss per unit area presuming that the insulating material has a maximum temperature of 1200°C.

Question-AnswerCategory: Heat And Mass TransferA reactor's wall 320mm thick, is made up of an inner layer of fire brick (k = 0.84W/m°C) covered with a layer of insulation (k = 0.16W/m°C). The reactor operates at a temperature of 1325°C at the atmospheric temperature of 25°C. i. Calculate the thickness of brick and insulation. ii. Heat loss per unit area presuming that the insulating material has a maximum temperature of 1200°C.
GME asked 4 weeks ago

A reactor’s wall 320mm thick, is made up of an inner layer of fire brick (k = 0.84W/m°C) covered with a layer of insulation (k = 0.16W/m°C). The reactor operates at a temperature of 1325°C at the atmospheric temperature of 25°C.
 
i. Calculate the thickness of brick and insulation.
 
ii. Heat loss per unit area presuming that the insulating material has a maximum temperature of 1200°C.

1 Answers
Sazid Ahmad answered 4 weeks ago

Given Data 
The thickness of the reactor wall, t=320 mm
The thermal conductivity, K1= 0.84W/m°C  k2 = 0.16W/m°C
The reactor temperature Ti=1325°C
The atmospheric temperature, T0=25°C
The maximum temperature of insulating material, Tmax=1200°C
 

 

Mechanical Engineering homework question answer, step 2, image 1
Substitute in above equations we get
LA=114.7mm  and LB=205.3mm

 

Heat loss per unit area,
Mechanical Engineering homework question answer, step 3, image 1

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