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A reactor's wall 320 mm thick, is made up of an inner layer of fire brick (k = 0.84 W/m°C) covered with a layer of insulation (k -0.16 W/m°C). The reactor operates at a temperature of 1325°C and the ambient temperature is 25°C. () Determine the thickness of fire brick and insulation where the interface temperature is 1200°C (ii) Calculate the heat loss

Question-AnswerCategory: Heat And Mass TransferA reactor's wall 320 mm thick, is made up of an inner layer of fire brick (k = 0.84 W/m°C) covered with a layer of insulation (k -0.16 W/m°C). The reactor operates at a temperature of 1325°C and the ambient temperature is 25°C. () Determine the thickness of fire brick and insulation where the interface temperature is 1200°C (ii) Calculate the heat loss
GME asked 4 weeks ago

A reactor’s wall 320 mm thick, is made up of an inner layer of fire brick (k = 0.84 W/m°C) covered with a layer of insulation (k -0.16 W/m°C). The reactor operates at a temperature of 1325°C and the ambient temperature is 25°C. () Determine the thickness of fire brick and insulation where the interface temperature is 1200°C (ii) Calculate the heat loss
 

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Q.1
A reactors wall 320 mm thick, is made up of an inner layer of fire brick (k = 0.84 W/m°C) covered with a layer of
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1 Answers
Sazid Ahmad answered 4 weeks ago

 
 
Given :
Reactors wall
= 320mm Thick
Thermal Conductivity =K,=0.84 W/m
K2 = 0.16 W/ms
0.84 W/mic
Ti = 1325c
Ta= as c
+2=120C1325-2s)
LA Lo
0.8U 0.16
| 325-1200
LA
0.31
r
Ly t Lb = .32
. Lp = 0.32-LA
125
1300
1
084
LA
084
4 032-Le
O.I
(300
1.14LA + LB =
0.32-0.1147
0-2053 m
205.3mm
.: Q = q =
1325-25
0.1147
02053
+
0.84
0.16
915.7 W/m²
Heat Loss ñ 916 W/m2

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