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A hydraulic press has a ram of 290 mm diameter and a plunger of 4.8 cm diameter. Find the weight lifted by hydraulic press in Kilo Newton, when the force applied at the plunger is 4×10-4 MN. If diameters of plunger and ram increased by 15% then find the weight lifted by hydraulic press. Justify the answer with respect to the diameter.

Question-AnswerCategory: Fluid MechanicsA hydraulic press has a ram of 290 mm diameter and a plunger of 4.8 cm diameter. Find the weight lifted by hydraulic press in Kilo Newton, when the force applied at the plunger is 4×10-4 MN. If diameters of plunger and ram increased by 15% then find the weight lifted by hydraulic press. Justify the answer with respect to the diameter.
Kristin asked 1 year ago

A hydraulic press has a ram of 290 mm diameter and a plunger of 4.8 cm diameter. Find the weight lifted by hydraulic press in Kilo Newton, when the force applied at the plunger is 4×10-4 MN. If diameters of plunger and ram increased by 15% then find the weight lifted by hydraulic press. Justify the answer with respect to the diameter.

Q3: A hydraulic press has a ram of 290 mm diameter and a plunger of 4.8 cm diameter. Find the weight lifted by hydraulic pres

 
 

1 Answers
MG answered 1 year ago

 

Q ©: Hydraulic press a Ram diameter D=290mm nm D = 0.29 m Qe diameter da da yo8cm orouom - Force on Plunger F = UX10-4 MN FaSolve & Let W= weight lifted by Hydraulic press 1Lt Plunger Hydraulic press works on the principle of Rascal law. Same pre 8sт 9 - тр* • Ая (о. 29° з (А= o •o66 os19 m2 Ј - а = та* - а- шx cor oy0) т т т। = = 180966-10-3 m2 = 1. 8०१66x15-3 २- By Paseal law W-g W= 4008 0:0660519 1.00966X10-3 » T W = 14 600.69 N = 146oon J=14.6kN = 14.6 KN weight lifted by Hydraulic press. B so . If diameters of Plunger and ram increased by 15%. let Da= new diameter of Ram da= new diameter of Plunger» » Da= 1.15D (156). PJ Dg= 1.158 0.29 [Da=0.3335m ] (da= 1.150 da = 115800048 de 20105527 = a o3 . area of Plunger with 15% increase diameter , 29= I do? > aga Î x 0.0552j2g aga 8.3931 X10-3 m2 /Area of ㅋ Ram (A2) ㅋ Ag 욕D ㅋ Ag= 44 xC013335)2 ㅋ 1 Ag= 00087 353 m2 Ag=..008 7 353 m2- Bя eqqabran O let Wa = weight lift by press - with 150% diameter p. aq a a Wa= 400 x 01087353 2.3931X10-3 Wa = 14 6001 8IN,Conclusion & W= 146oon = 14.6 KN Wa= 196oon =1416 IN → same force lift by Hydraulic pre 88 as the diameters of ram and Plunge

 

 

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