A force of 250 N pulls a body of weight 500 N up an inclined plane, the force being applied parallel to the plane. If the inclination of the plane to the horizontal is 15°, find the coefficient of friction.

1 Answers

**Step: 1**

**Force, F = 250 N pulling the body of weight **

**W = mg = 500 N up an inclined plane parallel to the plane which makes an angle 15o with the horizontal.**

**Step: 2**

**From the figure we can make equations,**

**N = 500cos15 **

**250 = f+500sin15 (f=uN is the frictional force)**

**u 500 cos15 = 250−500sin15 **

**u=120.6/500cos15 = 0.966**

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