A close-coiled helical spring has a mean coil diameter 10 times the diameter of the wire. A load of
3,5 kN causes a deflection of 95 mm and maximum stress of 400 MPa.
Take G = 80 GPa.
Calculate:
5.1 The wire diameter, (3)
5.2 The mean coil diameter, (3)
5.3 The number of coils, (3)
5.4 The energy absorbed when subjected to the maximum load, and (3)
5.5 The stiffness of the spring. (3)