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A bracket for supporting the travelling crane is shown in Figure given below. The bracket is fixed to the steel column by means of four identical bolts, two at A and two at B. The maximum load that comes on the bracket is 5 kN acting vertically downward at a distance of 250 mm from the face of the column. The bolts are made of steel 40C8 (Syı = 380 N/mm²) and the factor of safety is 5. Determine the major diameter of the bolts on the basis of maximum principal stress. Assume (dc = 0.8d).

Question-AnswerCategory: Machine DesignA bracket for supporting the travelling crane is shown in Figure given below. The bracket is fixed to the steel column by means of four identical bolts, two at A and two at B. The maximum load that comes on the bracket is 5 kN acting vertically downward at a distance of 250 mm from the face of the column. The bolts are made of steel 40C8 (Syı = 380 N/mm²) and the factor of safety is 5. Determine the major diameter of the bolts on the basis of maximum principal stress. Assume (dc = 0.8d).
John asked 3 months ago

A bracket for supporting the travelling crane is shown in Figure given below. The bracket is fixed to the steel column by means of four identical bolts, two at A and two at B. The maximum load that comes on the bracket is 5 kN acting vertically downward at a distance of 250 mm from the face of the column. The bolts are made of steel 40C8 (Syı = 380 N/mm²) and the factor of safety is 5. Determine the major diameter of the bolts on the basis of maximum principal stress. Assume (dc = 0.8d).

1 Answers
ਸਾਜਿਦ ਅਹਿਮਦ answered 3 months ago

solution Sky 250mm 75mm I А A NA fi, P2! А Те, 3oomm 15x2.50m) , sky. 75mm -B44P2 Pul Boy B С. q Py f Giren data 2 Bolts at Td = ${X103 Ix d2 58103 X d2 2 Td 1591.55 M/m² m2 d2 A total moment of M= 5x250 KH-mm M=56250 KH-mm will be applied at Centark= K 5X250 2812 +282² (N-m) 2x10.0752 +0.3752) (m2) IK = 4273.50 Mm. - SX250 P = kr I Pil 임 4273-50 X 0.375 = 1602:56 N 1.602as. Now, consider Consider a spess element Td > on >d 2 - on=2039.73 N/m2 d2 Td 1591.55 N/m2 d2 Maximum Principal spess is giThe Maxinem Principal stem is :- 61 N/m2 2902.144 = d2 Syt = 380 N/mm2 Syt = 380X106 N/m² Allowable yield stess is given by Sdmajol = d 0.8 6.264 = 2 dingor = 7.83mm The major diameter is 7.83 mm stess theory. Using maximum Principal

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